split 语法

ALTER FUNCTION [dbo].[F_SPLIT](  @str VARCHAR(MAX) ,  @split VARCHAR(10))    /***********************************************************名称: [F_SPLIT]功能描述 根据特定字符切割字符串输入参数：@str  需切割字符串@split 特定字符返回值根据特定字符切割字符串后的一张表 SELECT * FROM [F_SPLIT]('1,2,3',',')***********************************************************/RETURNS TABLE    AS RETURN    ( SELECT    B.id      FROM      ( SELECT    [value] = CONVERT(XML , '
     
      ' + REPLACE(@str , @split , '
     
     
      ')                            + '
     ')                ) A      OUTER APPLY ( SELECT  id = N.v.value('.' , 'varchar(100)')                    FROM    A.[value].nodes('/v') N ( v )                  ) B    )

以with 语法来分割

alter FUNCTION [dbo].[UF_SpliteIntToTable]  (      @String VARCHAR(8000)  )  RETURNS @Table TABLE (Id INT)  AS  BEGIN  DECLARE @String VARCHAR(100); DECLARE @SpliteChar AS CHAR(1) = ',';                WITH TempTable AS      (          SELECT CAST(SUBSTRING(@String,1,CHARINDEX(@SpliteChar,@String,1) - 1) AS INT) AS item,          SUBSTRING(@String,CHARINDEX(@SpliteChar,@String,1) + 1, LEN(@String)) + @SpliteChar AS list            UNION ALL            SELECT CAST(SUBSTRING(list,1,CHARINDEX(@SpliteChar,list,1) - 1) AS INT) AS item,          SUBSTRING(list,CHARINDEX(@SpliteChar,list,1) + 1, LEN(list)) AS list          FROM TempTable          WHERE LEN(TempTable.list) > 0      )  end

 其他：

--方法0：动态SQL法

declare @s varchar(100),@sql varchar(1000)

set @s='1,2,3,4,5,6,7,8,9,10'

set @sql='select col='''+ replace(@s,',',''' union all select ''')+''''

PRINT @sql

exec (@sql)

 

if exists (select * from dbo.sysobjects where id = object_id(N'[dbo].[f_splitSTR]') and xtype in (N'FN', N'IF', N'TF'))

drop function [dbo].[f_splitSTR]

GO

--方法1：循环截取法

CREATE FUNCTION f_splitSTR(

@s   varchar(8000),   --待分拆的字符串

@split varchar(10)     --数据分隔符

)RETURNS @re TABLE(col varchar(100))

AS

BEGIN

 DECLARE @splitlen int

 SET @splitlen=LEN(@split+'a')-2

 WHILE CHARINDEX(@split,@s)>0

 BEGIN

  INSERT @re VALUES(LEFT(@s,CHARINDEX(@split,@s)-1))

  SET @s=STUFF(@s,1,CHARINDEX(@split,@s)+@splitlen,'')

 END

 INSERT @re VALUES(@s)

 RETURN

END

GO

 

if exists (select * from dbo.sysobjects where id = object_id(N'[dbo].[f_splitSTR]') and xtype in (N'FN', N'IF', N'TF'))

drop function [dbo].[f_splitSTR]

GO

--方法2：使用临时性分拆辅助表法

CREATE FUNCTION f_splitSTR(

@s   varchar(8000),  --待分拆的字符串

@split varchar(10)     --数据分隔符

)RETURNS @re TABLE(col varchar(100))

AS

BEGIN

 --创建分拆处理的辅助表(用户定义函数中只能操作表变量)

 DECLARE @t TABLE(ID int IDENTITY,b bit)

 INSERT @t(b) SELECT TOP 8000 0 FROM syscolumns a,syscolumns b

 INSERT @re SELECT SUBSTRING(@s,ID,CHARINDEX(@split,@s+@split,ID)-ID)

 FROM @t

 WHERE ID<=LEN(@s+'a') 

  AND CHARINDEX(@split,@split+@s,ID)=ID

 RETURN

END

GO

 

if exists (select * from dbo.sysobjects where id = object_id(N'[dbo].[f_splitSTR]') and xtype in (N'FN', N'IF', N'TF'))

drop function [dbo].[f_splitSTR]

GO

if exists (select * from dbo.sysobjects where id = object_id(N'[dbo].[tb_splitSTR]') and objectproperty(id,N'IsUserTable')=1)

drop table [dbo].[tb_splitSTR]

GO

--方法3：使用永久性分拆辅助表法

--字符串分拆辅助表

SELECT TOP 8000 ID=IDENTITY(int,1,1) INTO dbo.tb_splitSTR

FROM syscolumns a,syscolumns b

GO

--字符串分拆处理函数

CREATE FUNCTION f_splitSTR(

@s     varchar(8000),  --待分拆的字符串

@split  varchar(10)     --数据分隔符

)RETURNS TABLE

AS

RETURN(

 SELECT col=CAST(SUBSTRING(@s,ID,CHARINDEX(@split,@s+@split,ID)-ID) as varchar(100))

 FROM tb_splitSTR

 WHERE ID<=LEN(@s+'a') 

  AND CHARINDEX(@split,@split+@s,ID)=ID)

GO

 

--方法4：利用sql server2005的OUTER APPLY

CREATE FUNCTION [dbo].[ufn_SplitStringToTable]

(

  @str VARCHAR(MAX) ,

  @split VARCHAR(10)

)

RETURNS TABLE

    AS 

RETURN

    ( SELECT    B.id

      FROM      ( SELECT    [value] = CONVERT(XML , '<v>' + REPLACE(@str , @split , '</v><v>')

                            + '</v>')

                ) A

      OUTER APPLY ( SELECT  id = N.v.value('.' , 'varchar(100)')

                    FROM    A.[value].nodes('/v') N ( v )

                  ) B

    )

 

备注说明：

方法4必须在sql server2005下才可以运行